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Ira Lisetskai [31]
4 years ago
12

Help! more division pretty easy now do it!

Mathematics
2 answers:
schepotkina [342]4 years ago
8 0

Answer:

448 R50

Step-by-step explanation:

NARA [144]4 years ago
7 0

Answer: 448

All you need to do is plug that into a calculator and you’ll get the answer

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Rubys market sells smoked meats by the pound the prices for several different meals are shown in the table.
vichka [17]
Question 1: <span>how much more does 1 1/4 pounds of beef cost than 1 1/4 pounds of turkey?

$4.25/pound (beef) / 4 = $1.06 per 1/4 lb = $4.25 + $1.06 = $5.31 per 1 1/4 lb
$2.85/pound (turkey) / 4 = $0.71 per 1/4 lb = $2.85 + $0.71 = $3.56 per 1 1/4 lb

$5.31 - $3.56  = $1.75 (the beef is more expensive by this much compared to the 1 1/4 lb of turkey) 

Question 2: </span><span>question 2. brad has 10 dollars to spend at ruby's. He orders 1/2 pound of sausage and 1 1/4 pounds of chicken. How much money will he brad have after he pays for this order?

$3.25 / 2 = $1.62 per 1/2 pound of sausage 
$2.50 / 4 = $0.62 per 1/4 lb of chicken + $2.50 = $3.13 per 1 1/4 lb of chicken

$1.62 (1/2 lb sausage) + $3.13 (1 1/4 lb chicken) =$4.75
$10 (budget) - $4.75 (total expense)  = $5.25 (Brad will have this much left from his budget)</span>
3 0
3 years ago
Suppose an unknown radioactive substance produces 8000 counts per minute on a Geiger counter at a certain time, and only 500 cou
mariarad [96]

Answer:

The half-life of the radioactive substance is of 3.25 days.

Step-by-step explanation:

The amount of radioactive substance is proportional to the number of counts per minute:

This means that the amount is given by the following differential equation:

\frac{dQ}{dt} = -kQ

In which k is the decay rate.

The solution is:

Q(t) = Q(0)e^{-kt}

In which Q(0) is the initial amount:

8000 counts per minute on a Geiger counter at a certain time

This means that Q(0) = 8000

500 counts per minute 13 days later.

This means that Q(13) = 500. We use this to find k.

Q(t) = Q(0)e^{-kt}

500 = 8000e^{-13k}

e^{-13k} = \frac{500}{8000}

\ln{e^{-13k}} = \ln{\frac{500}{8000}}

-13k = \ln{\frac{500}{8000}}

k = -\frac{\ln{\frac{500}{8000}}}{13}

k = 0.2133

So

Q(t) = Q(0)e^{-0.2133t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.2133t}

0.5Q(0) = Q(0)e^{-0.2133t}

e^{-0.2133t} = 0.5

\ln{e^{-0.2133t}} = \ln{0.5}

-0.2133t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.2133}

t = 3.25

The half-life of the radioactive substance is of 3.25 days.

7 0
3 years ago
38=x+10+9-3<br>I don't get this question​
Lilit [14]

Answer:

so is that all it says, if its not thats not a question because its already answered

Step-by-step explanation:

4 0
4 years ago
6 + 5/9 what is the answer
svetoff [14.1K]

Answer:

6.5 i think im not smart

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP QUICK!! If the local tax is 3% and you get paid $678 biweekly, what is the local tax deduction?
Anastasy [175]

tax reduction: $20.34

amount you're paid minus tax: $657.66

4 0
4 years ago
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