log (m + n) = log m+ log n and proved it m =n/n-1
Given;
If log (m + n) = log m+ log n
To show that the m =n/n-1
Now, According to the question:
We know that,
Log (m + n) = log m + log n
Log (m + n ) = log (mn). [log a + log b = log ab ]
Cancelling the log on both sides.
then,
m + n = mn
=> n = mn - m
=> n = m (n - 1)
=> m = n / n - 1
Hence Proved
log (m + n) = log m+ log n and proved it m =n/n-1
What is Logarithm?
A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.
Learn more about Logarithm at:
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Answer:
6 AND 12
Step-by-step explanation:
3 x 2 = 6
3 x 4 = 12
My estimated answer for 1 is x=1.59 or x=-1.26 and my exact answer is (in word form) x= 1 plus or minus the square root of 73 over 6. my estimated answer for 2 is x=-0.34 or x=1.74 and my exact answer (in word form) is x= -7 plus or minus the square root of 109 over -10. I took a picture of my work and hopefully you can read it
Let's solve your inequality step-by-step.<span><span><span>−1</span>+<span>4y</span></span><31</span>Step 1: Simplify both sides of the inequality.<span><span><span>4y</span>−1</span><31</span>Step 2: Add 1 to both sides.<span><span><span><span>4y</span>−1</span>+1</span><<span>31+1</span></span><span><span>4y</span><32</span>Step 3: Divide both sides by 4.<span><span><span>4y</span>4</span><<span>324</span></span><span>y<<span>8</span></span>
