Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
</span>
Answer: 1/8 km
Step-by-step explanation:
3/8 * 1/3 = 1/8
F(x)=x^2-3x+1/2, if f(4)
Substitute x with 4, to get
f(x)=x^2-3x+1/2
f(4)=4^2-3(4)+1/2
f(4)=16-12+1/2
f(4)=4+1/2
f(4)=4 1/2 or 4.5. Hope it help!
