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Zielflug [23.3K]

3 years ago

7

PRETTY EASY PLS HELP I BEG U

2 answers:

Step2247 [10]3 years ago

6 0

Answer:

C

Step-by-step explanation:

lbvjy [14]3 years ago

3 0

Answer:

Step-by-step explanation:

110 I think

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M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB

marusya05 [52]

X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72

7 0

3 years ago

Two samples of fish from a pond were analyzed. The second sample was taken six months after the first sample.

Agata [3.3K]

Answer:

B.

D.

E.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The sum of three consecutive numbers is 36. What are the numbers?

Yuliya22 [10]

Answer:

11, 12, and 13

Step-by-step explanation:

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3 years ago

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Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).

ad-work [718]

<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

$(3^56^8)(3^96^{10})$

Given Conner's work is:

$(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}$

We have to check if this work is correct

Yes, Conner work is correct

From given,

$(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}$

Use the following law of exponent

$a^m \times a^n = a^{m+n}$

Therefore,

$3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}$

<em><u>Given Jana's work is:</u></em>

$(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}$

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0

3 years ago

Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

$\mu$ = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

$F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2$

La aceleración del bloque es $10.9\ \text{m/s}^2$ .

8 0

3 years ago