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elena-14-01-66 [18.8K]
3 years ago
12

Calculate the data rate capacity for a 2400 baud signal where there are M=8 levels per symbol. a. 2400 bps b. 4800 bps c. 7200 b

ps d. 9600 bps
Computers and Technology
1 answer:
zimovet [89]3 years ago
7 0

Answer:

C. 7200 bps.

Explanation:

In networking, transmission lines or connectors and ports operates at a specific speed based on the port type and the cable or medium of transmission.

Baud rate is a concept in digital information technology that defines the rate of symbol per channel during transmission. The bit or data rate is the number of bits transfered in a link per second.

The relationship between baud rate and bit rate is;

Bit rate = baud rate x number of symbol bit level

To get the bit rate of a 2400 baud signal with symbol level = 8 = 2^3

Bit rate = 2400 x 3. = 7200 bps.

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rewona [7]

Answer:

False

Explanation:

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<u>Following are the example is given below in C++ Language </u>

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {     return 3.14*r*r;  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 3.5;  

 double t= r1.area(); // calling

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   return 0;  

}  

Output:

compile time error is generated

<u>The correct program to access the private member of class is given below </u>

#include<iostream>   // header file

using namespace std;  

class Rectangle

{    

   private:  

       double r; // private member  

   public:      

       double  area()  

       {    

r1=r;

double t2=3.14*r2*r2;

return(t2); // return the value  

       }        

};  

int main()  

{    

  Rectangle r1;// creating the object  

   r1.r = 1.5;  

 double t= r1.area(); // calling

cout<<" Area is:"<<t;  

   return 0;  

}  

Therefore the given statement is False

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