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irinina [24]
2 years ago
12

Output devices reproduce or display which of the following

Computers and Technology
2 answers:
Trava [24]2 years ago
8 0

D. Computer Systems

Hope this helped :)

Minchanka [31]2 years ago
3 0

Answer: Processing results.

Explanation: This lesson is about engineering and technology and working with systems, making problems into ideas. The question is looking for: "What is shown on the output device"? Or what is displayed on it.

You might be interested in
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
2 years ago
What should you do if a headset plugged into your computer is not working properly?
Alex777 [14]

If a headset plugged into computer is not working properly than one can go for updating the device driver. The correct option is B.

<h3>What is a device driver?</h3>

A device driver is a type of software application that allows one hardware device (such as a computer) to communicate with another hardware device (such as a printer). A device driver is indeed referred to as a software driver.

A driver, also known as a device driver, is a collection of files that instructs a piece of hardware on how to operate by communicating with a computer's operating system.

Every piece of hardware, from internal computer components like your graphics card to external peripherals like a printer, requires a driver.

If a headset plugged into a computer is not working properly, the device driver can be updated.

Thus, the correct option is B.

For more details regarding device driver, visit:

brainly.com/question/14054807

#SPJ12

8 0
1 year ago
Read 2 more answers
In case of rdt 3.0 Stop and Wait, suppose we send a packet of 1KB through 1 Gbps link and RTT=20 msec. Find the sender utilizati
Mamont248 [21]

Answer:

a. Utilization =  0.00039

b. Throughput = 50Kbps

Explanation:

<u>Given Data:</u>

Packet Size = L = 1kb = 8000 bits

Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps

RTT = 20 msec

<u>To Find </u>

a. Sender Utilization = ?

b. Throughput = ?

Solution

a. Sender Utilization

<u>As Given </u>

Packet Size =  L = 8000 bits

Transmission Rate = R = 1 Gbps = 1 x 10⁹ bps

Transmission Time = L/R = 8000 bits / 1 x 10⁹ bps = 8 micro-sec

Utilization =  Transmission Time / RTT + Transmission Time

                 =  8 micro-sec/ 20 msec + 8 micro-sec

                 =  0.008 sec/ 20.008 sec

Utilization =  0.00039

b. Throughput

<u>As Given </u>

Packet Size = 1kb

RTT = 20ms = 20/100 sec = 0.02 sec

So,

Throughput = Packet Size/RTT = 1kb /0.02 = 50 kbps

So, the system has 50 kbps throughput over  1 Gbps Link.

5 0
2 years ago
Determine the type of sampling (random, stratified, systematic,
Ann [662]

Answer:

a. Convenience

b. Random

c. Stratified

d. Systematic

Explanation:

Types of sampling:

  • Random:

The selection of sample is arbitrary and each member has an equal chance of selection.

  • Convenience

This selection does not take probability of selection into account rather focuses on the convenience and proximity of the member for selection.

  • Systematic

An ordered system is decided to choose the members for this sample.

  • Cluster

This sampling plan divided the population into groups, called clusters. A cluster is then randomly selected from the selected population.

  • Stratified

The members of the population are divided into groups, called strata. A random sample is drawn from each strata.

6 0
2 years ago
What is the relationship between a folder and a subfolder?
zhannawk [14.2K]

A sub folder is one layer under the folder - hence the prefix sub

3 0
3 years ago
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