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3 years ago

The lines shown below are parrel if the green line has a slope of -3/7 what is the slope of the red line

Mathematics

2 answers:

Fofino [41]3 years ago

5 0

Answer:

-3/7

Step-by-step explanation:

If two lines are parallel, it is determined that both of their slopes are the same. In this case, they are and one slope is given so, the other is the same.

Lorico [155]3 years ago

5 0

-3/7

If lines are parallel that means the slope would be the same

If it's was perpendicular then the slope would've been 7/3

Hope this helps!

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OverLord2011 [107]

Answer:

d. 1

Step-by-step explanation:

The amplitude of such a function is the magnitude of the coefficient of the sine function.

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3 years ago

Find the limit of the function by using direct substitution as X approaches one lim(x^2-8x -2)

Leno4ka [110]

Answer:

$lim_{x \to 1} x^2 -8x -2 =-9$

Step-by-step explanation:

For this case we want to find the following limit:

$lim_{x \to 1} x^2 -8x -2$

And we can find the limit distirbuting into each term like this:

$\lim_{x \to 1} x^2 -8 lim_{x \to 1} x -lim_{x \to 1} 2$

And replacing we got:

$1^2 - 8*1 -2 = 1-8-2 = -9$

So then the final answer for this case is:

$lim_{x \to 1} x^2 -8x -2 =-9$

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4 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by: