2 plus ( 9 to the power 2 -4

Can you please help me on -5(-4r-6)=5(6-r)

Wewaii [24]

The answer you are looking for is no solution.

To find this, you first distribute the -5 into the parenthesis (-4r - 6). -5 x -4r = 20r and -5 x -6 = 30.Next, distribute the 5 into the parenthesis (6 - r). 5 x 6 = 30 and 5 x r = 5r.

The equation says 20r + 30 = 5r + 30. Now you solve for r.Subtract 5r from both sides. This leaves the equation to say 15r + 30 = 30. Then subtract 30 from both sides, to get 15r = 0.

At this point, since there is a zero on the opposite side of the variable, you can assume it will be no solution, since multiplying or dividing 0 by anything, is 0. However, I'll finish the problem, to show that it is no solution.

Divide 15 from both sides, leaving r = 0, which is no solution.

I hope this helps!

4 0

4 years ago

At what width does a totality of a Solar Eclipse span?

I am Lyosha [343]

I think you're talking about the black spot on the surface of the Earth,
where the end of the Moon's shadow falls, and anybody inside that
circle sees the Sun completely covered for a few minutes.

The size of that spot varies. It depends on exactly how far the Moon
is from the Earth, and exactly how far both bodies are from the Sun.

The longest possible totality viewed from a single location is about
7-1/2 minutes, when all the geometry is just right. Then, I believe,
the black spot on the Earth's surface is something like 170 miles
across, moving at around 24 miles a minute, or 1,460 miles per hour.

8 0

3 years ago

Which absolute value function, when graphed, will be wider than the graph of the parent function, f(x) = |x|? f(x) = |x| + 3 f(x

Dafna1 [17]

Since I am obtaining this message when try ot submit the answer:

"Oh no! Something went wrong while adding your answer
It appears that your answer contains either a link or inappropriate words. Please correct and submit again!"

I copied the answer in a pdf file. Please, see the answer attached.

Download pdf

8 0

4 years ago

Read 2 more answers

The graph shows the functions f(x), p(x), and g(x):

viktelen [127]

Part A: What is the solution to the pair of equations represented by p(x) and f(x)? (3 points)
(3,1)
Part B: Write any two solutions for f(x). (3 points)
(0,-5) (1, -3)
Part C: What is the solution to the equation p(x) = g(x)? Justify your answer. (4 points)
(1,3)
because they intersect at that point

8 0

3 years ago

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

4 years ago