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Ghella [55]
3 years ago
5

why do we as humans judge each other? Like for real can't we just see each other's differences as something cool and unique and

just appreciate each other's existence?​
Social Studies
1 answer:
Pie3 years ago
3 0
It’s the human nature and an instinct to sin.
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PLEASE HELP 100 POINTS!!!
Alenkinab [10]

Answer:False

Explanation:

They did have a system of writing called cuneiform.

6 0
3 years ago
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Which colonies had the strictest slave codes?
Inessa [10]
The colonies that had the strictest slave codes were America and Britain
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how did General Robert E. Lee was able to prolong the life of the Confederacy after the Battle of Hampton Roads.
ANEK [815]

Answer:

The south had better military generals than the north, Robert E. Lee being one of them. They also had more military schools located in the south, and people tended to fight for the side that their home support. Robert E. Lee was known as the best general at the time.:

6 0
3 years ago
What is the term for the presidents refusal to spend money for a program that congress has funded.?
aalyn [17]

The correct answer is impoundment.

The Impoundment of appropriated funds is one of those ideas that has mostly gone away. A law was passed after it was perceived that President Nixon was abusing the impoundment powers.

Presidents are more likely to now use a line-item veto to accomplish a similar end to impoundment.

3 0
3 years ago
Suppose that scientists discover an asteroid that is 2.0 AU from the sun. If 1 AU - 150 million km, how long would the asteroid'
Mice21 [21]

Answer:

2.84*10^-3 years = 0.00284*10^-3 years

Explanation:

To find the orbital period you use the following formula:

T=\sqrt{\frac{4\pi^2r^3}{GM}}

r: 2.0A = 2.0(1.5*10^11m)=3*10^11 m

G: Cavendish constant = 6.67*10^-11 Nm^2/kg^2

M: mass of the sun = 1.98*10^30 kg

T=\sqrt{\frac{4\pi^2(3*10^{11}m)^3}{(6.67*10^{-11}Nm^2/kg^2)(1.98*10^{30}kg)}}\\\\T=89839.27\ s

Next, you calculate the time in seconds of one Earth's year:

1\ year=365days*\frac{24\ h}{1\ day}*\frac{3600\ s}{1\ h}=31536000\ s

thus, you use this value to find the orbital period of the asteroid in Earth's year:

T=89839.27\ s*\frac{1\ year}{31536000\ s}=2.84*10^{-3}\ years

5 0
3 years ago
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