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dmitriy555 [2]
3 years ago
12

A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollin

ated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 187, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
A. 22B. 33C. 55D. 77E. 88
Mathematics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

B. 33

Step-by-step explanation:

Let the number of Fuji trees be F, the number of gala be G and the total number of trees be x.

10% cross pollinated, this means 1/10 cross pollinated or 0.1x

Number of Fuji plus cross pollinated is 187.

And cross pollinated is 3/4 of total or let’s say 0.75 of total which is 0.75x

Now, adding 0.1x + 0.75x would equal 187

0.85x = 187

x = 187/0.85 = 220 trees

The total number of trees is 220.

The number of gala trees is thus 220 - 187 = 33 trees

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P=0.4125

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In this case we have a uniform probability. In the graph the horizontal axis represents the possible values of the variable x and the vertical axis represents the probability P(x).

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