By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.
<h3>How to prove this point lies on the unit circle?</h3>
In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:
Reference angle = 180 - θ
Reference angle = 180 - 120
Reference angle = 60°.
For the coordinates, we have:
sin(-120) = -sin(60) = -1/2.
cos(-120) = -cos(60) = -√3/2.
By applying Pythagorean theorem, we have:
z² = x² + y²
z = √((-1/2)² + (-√3/2)²)
z = √(1/4 + 3/4)
z = √1
z = 1.
Read more on unit circle here: brainly.com/question/9797740
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I think the answer is 4x - 15 = 6 + 1/2x
Answer:
<em>a</em><em>}</em><em>4</em><em>/</em><em>3</em>
<em>b</em><em>}</em>
<em>c</em><em>}</em><em>-</em><em>1</em><em>/</em><em>4</em>
Step-by-step explanation:
a}4-c/4-(2+b)
putting the values of b and c n its place
4-(-4)/4-(2-4)
4+4/4-(-2)
8/4+2
8/6
4/3 or 1.33
b}IDK SORRY
c} y-x+5+y/4
-1-4+5-1/4
-6+5/4
-1/4
1) Solving for x, the following equation:
We're going to isolate the x variable on the left:
