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noname [10]
2 years ago
15

Find the volume of the square pyramid shown. Round to the nearest tenth if necessary.

Mathematics
1 answer:
Butoxors [25]2 years ago
4 0
Formula
The formula for a pyramid is V = 1/3 * B * h

B = s * s of the square bottom
s = 10

B = 10*10
B = 100 square feet.

Height.
The height is not given. You find it using a^2 + b^2 = c^2
a = 1/2 length of the side of the base
b = height
c = 13^2

If you draw a line to the midpoint of the base form the base of the height, you get 5. You have to read that a couple of times. I don't know if you can see this or not. 
AC = 10
B is the midpoint of AC that means that BD = 5
BH = 13 Given
We need HD

Use the pythagorean theorem
HD^2 + BD^2 = BH
HD^2 + 5^2 = 13^2
HD^2 + 25 = 169
HD^2 = 169 - 25
HD^2 = 144 Take the sqrt of both sides.
HD = sqrt(144)
HD = 12

Find the Volume
V = 1/3 * B * H
V = 1/3 * 100 * 12
V = 1/3 * 1200
V = 400

Answer
V = 400 square feet <<< answer


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Answer:

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Step-by-step explanation:

From the question we are told that

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Generally the sample proportion is mathematically represented as

      \^ p = \frac{44}{118}

=>     \^ p =0.3729

Generally given that the confidence level is  95% the level of significance is mathematically represented as

       \alpha  =  (100 -95) \%

=>     \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

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Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{p(1 - p)}{n} }

=>   E =  1.96 * \sqrt{\frac{0.3729(1 - 0.3729)}{118} }

=>    E = 0.0872

Generally 95% confidence interval is mathematically represented as  

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=>    0.3729 -0.0872<  p <  0.3729 +0.0872

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5 0
3 years ago
Secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40o, arc AB = 60o, and arc BC = 160
s344n2d4d5 [400]

Answer:

C. 130^{\circ}

Step-by-step explanation:

Please find the attachment.

We have been given that secants AC and DB intersect at point E inside the circle. Given that the measure of arc CD = 40^o, arc AB = 60^o, and arc BC = 160^o. We are asked to find the measure of angle AED.

We know that the measure of angle formed by two intersecting secants is half the sum of measure of the arcs by intercepted by the angle and its vertical angle.    

\angle AED=\frac{\widehat{BC}+\widehat{AD}}{2}

Let us find measure of arc AD by subtracting measure of given arcs from 360 degrees as:

\widehat{AD}=360^{\circ}-(60^{\circ}+40^{\circ}+160^{\circ})

\widehat{AD}=360^{\circ}-(260^{\circ})

\widehat{AD}=100^{\circ}

\angle AED=\frac{160^{\circ}+100^{\circ}}{2}

\angle AED=\frac{260^{\circ}}{2}

\angle AED=130^{\circ}

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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Q # 1 simplify the expression
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<u>Answer</u>

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<u>Explanation</u>
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3 years ago
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