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Gnom [1K]
3 years ago
5

Which problem is represented by this inequality? 12x ≥ 48

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:

shoukd be x>= 4

Step-by-step explanation:

What are the answer choices?

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PLEASE HELP!!!<br> Use the figure and find PT.<br> PT = 7x - 24 and TQ = 6x-2
MAVERICK [17]

Answer:

PT= 130

Step-by-step explanation:

Since T is the midpoint of segment PQ,

PT = TQ

7x - 24 = 6x-2

Subtract 6x both sides and add 24 both sides

7x -6x - 24 = 6x -6x -2

x - 24 + 24 = -2 + 24

x= 22

Substitue x into PT

7(22) - 24

154 - 24

PT= 130

8 0
3 years ago
Which facts are true for the graph of the function below? Check all that apply.
Anna [14]

Answer:

It is increasing

The x-intercept is (1,0)

Apex!!!!

8 0
3 years ago
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I need the volume for 7 and 8
Sergio [31]

For number seven i got 1974m

and for number eight i got 374.13

4 0
3 years ago
Read 2 more answers
Please help
KonstantinChe [14]

Answer:

A

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Vertex: (2,1)(2,1)

Focus: (2,54)(2,54)

Axis of Symmetry: x=2

Hope it helped :)

5 0
3 years ago
Which choice is equivalent to the quotient below? sqrt 7/8* sqrt7/187/16/121/23/47/12
mario62 [17]

We can apply the following properties of radicals:

\begin{gathered} \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\Rightarrow\text{ Product property} \\ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}\Rightarrow\text{ Quotient property} \end{gathered}

Then, we have:

\begin{gathered} \text{ Apply the product property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7}{8}\cdot\frac{7}{18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7\cdot7}{8\cdot18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{49}{144}} \\ \text{ Apply the quotient property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{\sqrt[]{49}}{\sqrt[]{144}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{7}{12} \end{gathered}

Therefore, the choice that is equivalent to the given product is:

\frac{7}{12}

4 0
1 year ago
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