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zysi [14]
3 years ago
6

Between 02 30 and 05 30,the same day,the volume of water in a reservoir increased from 6000 L to 18 000 L.What was the average r

ate of increase in volume of water,giving your answer in L/h?
Mathematics
1 answer:
irinina [24]3 years ago
3 0

Answer:

4,000 L/h

Step-by-step explanation:

First we'll find the amount of the change.

18,000 - 6,000 = 12,000 L

The time of the volume change was 3 hours: 0230 - 0530

Since we're looking for liters per hour, we will divide the liters (12,000) by the hours (3)

12,000/3 = 4,000 L/h

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The answer is 168 logs.

1st row:          15 logs
2nd row:        18 logs
3rd row:         21 logs
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5th row:         27 logs
6th row:         30 logs
7th row:         33 logs

The sum of logs from each row is: 15 + 18 + 21 + 24 + 27 + 30 + 33 = 168 logs
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I think the answer is 2.The function is negative for all real values of x where x < –3 and where x > 1.

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Answer:

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Final volume = 960 - 72 = 888cm^3

 

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Step-by-step explanation:

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