Part 1:
After payment of $300, remaining balance = $2,348.62 - $300 = $2,048.62.
Interest accrued is given by:

Had it been $600 was paid, remaining balance = $2,348.62 - $600 = $1748.62. Interest accrued is given by:

Difference in interest accrued = $14.94 - $12.75 = $2.19
Part 2:
The present value of an annuity is given by:
![PV= \frac{P\left[1-\left(1+ \frac{r}{12} \right)^{-12n}\right]}{ \frac{r}{12} }](https://tex.z-dn.net/?f=PV%3D%20%5Cfrac%7BP%5Cleft%5B1-%5Cleft%281%2B%20%5Cfrac%7Br%7D%7B12%7D%20%5Cright%29%5E%7B-12n%7D%5Cright%5D%7D%7B%20%5Cfrac%7Br%7D%7B12%7D%20%7D)
Where PV is the amount to be repaid, P is the equal monthly payment, r is the annual interest rate and n is the number of years.
Thus,
![2348.62= \frac{600\left[1-\left(1+ \frac{0.0875}{12}\right)^{-12n}\right]}{\frac{0.0875}{12}} \\ \\ \Rightarrow 1-(1+0.007292)^{-12n}= \frac{2348.62\times0.0875}{12\times600} =0.028542 \\ \\ \Rightarrow(1.007292)^{-12n}=1-0.028542=0.971458 \\ \\ \Rightarrow \log(1.007292)^{-12n}=\log0.971458 \\ \\ \Rightarrow-12n\log1.007292=\log0.971458 \\ \\ \Rightarrow-12n= \frac{\log0.971458}{\log1.007292} =-3.985559 \\ \\ \Rightarrow n= \frac{-3.985559}{-12} =0.332130](https://tex.z-dn.net/?f=2348.62%3D%20%5Cfrac%7B600%5Cleft%5B1-%5Cleft%281%2B%20%5Cfrac%7B0.0875%7D%7B12%7D%5Cright%29%5E%7B-12n%7D%5Cright%5D%7D%7B%5Cfrac%7B0.0875%7D%7B12%7D%7D%20%20%5C%5C%20%20%5C%5C%20%5CRightarrow%201-%281%2B0.007292%29%5E%7B-12n%7D%3D%20%5Cfrac%7B2348.62%5Ctimes0.0875%7D%7B12%5Ctimes600%7D%20%3D0.028542%20%5C%5C%20%20%5C%5C%20%5CRightarrow%281.007292%29%5E%7B-12n%7D%3D1-0.028542%3D0.971458%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20%5Clog%281.007292%29%5E%7B-12n%7D%3D%5Clog0.971458%20%5C%5C%20%20%5C%5C%20%5CRightarrow-12n%5Clog1.007292%3D%5Clog0.971458%20%5C%5C%20%20%5C%5C%20%5CRightarrow-12n%3D%20%5Cfrac%7B%5Clog0.971458%7D%7B%5Clog1.007292%7D%20%3D-3.985559%20%5C%5C%20%20%5C%5C%20%5CRightarrow%20n%3D%20%5Cfrac%7B-3.985559%7D%7B-12%7D%20%3D0.332130)
Therefore, the number of months it will take to pay of the debt is 3.99 months which is approximately 4 months.
Answer: 204 students
Step-by-step explanation: To find out the greatest number of students that can fit at the 17 tables in the school cafeteria, we simply need to multiply the number of students that can fit at each table by the number of tables.
12 students can fit at 1 table and there are 17 tables.
So we have (12)(17) which is 204.
So the greatest number of students that can be seated din the cafeteria is 204 students.
4x+10y=-13...you have to add the variables that are the same and then subtract the 13 from 0