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anastassius [24]
3 years ago
13

Roesha spent $8.50 every hour for 2.5. Write and simplify and expression and to determine the total amount of money she spent

Mathematics
2 answers:
Mkey [24]3 years ago
8 0

Answer:

(-8.50)×2.5= -21.25

Step-by-step explanation:

Juli2301 [7.4K]3 years ago
6 0

8.50 +8.50= 17.00

1/2 of 8.50 is 4.25

so 17.00+4.25= 21.25

Roesha spent $21.25

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Results from previous studies showed 76% of all high school seniors from a certain city plan to attend college after graduation.
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Answer:

Yes, this indicate that the percentage has increased from that of previous studies.

Step-by-step explanation:

We are given that Results from previous studies showed 76% of all high school seniors from a certain city plan to attend college after graduation.

A random sample of 200 high school seniors from this city reveals that 162 plan to attend college.

<em>Let p = % of all high school seniors from a certain city who plan to attend college after graduation</em>

SO, <u>Null Hypothesis</u>, H_0 : p \leq 76%   {means that the percentage has not  increased from that of previous studies}

<u>Alternate Hypothesis,</u> H_a : p > 76%   {means that the percentage has increased from that of previous studies}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

              T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where,  \hat p = sample proportion of high school seniors from this city who  

                   plan to attend college = \frac{162}{200}  = 0.81

            n = sample of high school seniors = 200

So, <u><em>test statistics</em></u>  =  \frac{0.81-0.76}{{\sqrt{\frac{0.81(1-0.81)}{200} } } } }  

                               =  1.8025

<em>Now at 5% significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the percentage has increased from that of previous studies.

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