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postnew [5]
3 years ago
11

Check

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

Fraction Decimal

3/20. 15%

19/50. 38%

1/3. 33%

37/100. 37%

1/4. 25%

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What set of transformations is performed on triangle ABC to form triangle A′B′C′? (4 points)
fenix001 [56]

Answer:

i am on this exact question and i am confused myself because it seems like the answer should be "180 degree rotation with a translation of 5 units to the right" but that is not an option :/ so my best guess is either A or D hope this helps at all

Step-by-step explanation:

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it's quadratic

Step-by-step explanation:

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3 years ago
A snail crawls 2 3/4 inches in one minute . How far can it travel in 3 1/2 minutes?
Luden [163]

Answer: 5/6 inch/minute

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7 0
3 years ago
Factor linear expression 3c-9
Dafna1 [17]
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5 0
3 years ago
A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
dem82 [27]

Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

8 0
3 years ago
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