Question

Find the minimum value of C=x+3y

Answer 1

Hello there,

Use the first constraint to isolate y :

$9x+2y\geq 35$

$y \geq \frac{35-9x}{2}$

Now use the second one to isolate x :

$x+3y\geq 14$

$x\geq 14-3y$

You know that $x\geq 0$ and $y\geq 0$

So what's the minimum value of x it's 0 ! Same for y !

So substitute x by 0 and y by 0

$y\geq \frac{35}{2} =17.5$

$x\geq 14$

So the minimum value of C is :

$C=14+3*17.5$

$\boxed{C=66.5}$

Hope it helps !

Photon

Answer 2

Answer:

DNE

Step-by-step explanation:

If x and y may be any real number, there is no minimum value for C. It can approach negative infinity.

If C is a constant, and the domain of x is all real numbers, there is no minimum for y. It can approach negative infinity.

We're not sure what you want or what restrictions may exist. The given relation does not suggest any minimum. We'd have to say it Does Not Exist