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3 years ago

Write parametric equations of the line with the equation 4x-6y=-12 HELP FAST

Mathematics

2 answers:

Dmitry [639]3 years ago

7 0

Answer:

x = 3t

y = 2 + 2t

Step-by-step explanation:

Use any two points on the line:

Using intercepts would be easy

4x - 6y = -12

(-3,0) and (0,2)

Make a vector connecting these two: < 0 - -3, 2 - 0>

Direction vector: < 3, 2 >

Let the parameter be 't'

x = 0 + 3t

x = 3t

y = 2 + 2t

zimovet [89]3 years ago

4 0

Answer: x = t, y = 2t/3 + 2

Step-by-step explanation:

You want to write both x and y in terms of t

so if you rearrange 4x - 6y = -12 you get

-6y = -4x - 12

6y = 4x + 12

y = 2x/3 + 2

set x = t

and y = 2t/3 + 2

and that's it!

another one you could do is

x = t/2

y = t/3 + 2

or even

x = 3t/2

y = t + 2

i like this one the most because it looks more elegant

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A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0

3 years ago

What is the slope of a line parallel 18x+15y=90

luda_lava [24]

Answer:

-6/5

Step-by-step explanation:

Get y by itself to get the slope. So 18x+15y=90. Move 18x to the other side of the equation. Now you have 15y=-18x+90. Divide both sides by 15 to get y by itself. Now it's y= -18/15x + 6. Reduce -18/15 to the simplest fraction. You have y= -6/5x+6. Any number can replace the 6 in the equation to give you a parallel line...it's the slope that makes it parallel, not the y intercept. So y= -6/5x+10 or y=- -6/5x-1 would satisfy your parallel slope equation.

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2 years ago

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vichka [17]

The full cost would be £33.75

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2 years ago

1/8 +c= 4/5 what does c equal

Ray Of Light [21]

Answer:

c=27/40 = 0.675

Step-by-step explanation:

the statement give us the expression:

1/8 +c= 4/5

we subtract the term "1/8" both sides:

we have:

1/8 -1/8+c= 4/5-1/8

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