Question

Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 4%, each paper is worth 7%, each test is worth 12%, and the final is worth 46%.
(a) What is the average for a student with 72 on attendance, 96 on the first paper, 91 on the second paper, 94 on test 1, 73 on test 2, 100 on test 3, and 78 on the final exam?

Answer 1

Answer:

The student has total average of 83.89.

Step-by-step explanation:

The student has 72 out of 100 in the attendance and with a weightage of 4%, the average will be = $72 \times \frac{4}{100} = 2.88$

The student has 96 out of 100 in the first paper and with a weightage of 7%, the average will be = $96 \times \frac{7}{100} = 6.72$

The student has 91 out of 100 in the second paper and with a weightage of 7%, the average will be = $91 \times \frac{7}{100} = 6.37$.

The student has 94 out of 100 in the test 1 and with a weightage of 12%, the average will be = $94 \times \frac{12}{100} = 11.28$

The student has 73 out of 100 in the test 2 and with a weightage of 12%, the average will be = $73 \times \frac{12}{100} = 8.76$.

The student has 100 out of 100 in the test 3 and with a weightage of 12%, the average will be = $100 \times \frac{12}{100} = 12$.

The student has 78 out of 100 in the final exam and with a weightage of 46%, the average will be = $78 \times \frac{46}{100} = 35.88$

Therefore, the student has the total average of (2.88 + 6.72 + 6.37 + 11.28 + 8.76  + 12 + 35.88) = 83.89. (Answer)