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jenyasd209 [6]
2 years ago
12

eive 19. The school cafeteria uses 48 cans of peaches per day. How many cans of peaches will they use in 19 days? help​

Mathematics
1 answer:
Simora [160]2 years ago
3 0

Answer:

912

Step-by-step explanation:

All that needs to be done is multiply both numbers they give you.

48 x 19= 912

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The vertex form of the equation of a parabola is y=(x-5)+16. what is the standard form of the equation
kakasveta [241]

Answer:

x − y =  − 11

Step-by-step explanation:

4 0
3 years ago
a survey conducted in a school showed that 65% of the students walked to school. The remaining students took buses to school. Th
Feliz [49]
I fear that there is an error copying your assignment.  
65% of the students walked.  Are all of the other students on buses?  Are there both public buses AND private buses?
Assuming that you need to know BOTH kinds of buses, try this:

65% of the students walked, so since 100% - 65% = 35% then this means that 35% of the students were on buses.
Since we know that there are 360 more walkers than bus riders, then one equation we know is:  65% of S = 360 + 35% of S  (let S = total # of students)
              .65 S     = 360 + .35 S
           <u> - .35 S   </u>  =     <u>   - .35 S</u>      Subtract .35 S from both sides
             <u> .30  S   </u> = <u> 360</u>                 Divide both sides by .30 (or .3)
                .30           .30
                      S   =  1,200  so we know that this is the total number of students, but that is not what was asked.  
They want to know how many are on buses and specifically how many are on public buses, if I read this correctly.
   Since the walkers = 65% of 1,2000 and we know of means TIMES, then
                                  .65 (1,200) =  780 walkers
 1,200 total students minus 780 walkers = 420 bus riders

Now, if there is not a misprint and we really have to figure out the public bus riders as compared to the private bus riders, then remember the ratio from above in the question:   4 bus: 3 public buses
Now if I read this right, that means that 3/4ths of the bus riders were on public buses
so 3/4 of 420 means 3/4 times 420  = 3 times 105 = 315 public bus riders (which coincidentally leaves 105 private bus riders, but since they are private we don't know much about them.  Ha-Ha..... I made a lame joke.)

So your answer is 315 public bus riders



5 0
3 years ago
Read 2 more answers
How can I get help with linear equations with fractions? I dont remember how to solve​
xz_007 [3.2K]

Answer:

to find the missing number, compare both sides of the equation. If the variable terms are the same and the constant terms are different, then the equation has no solutions.

Step-by-step explanation:

to find the missing number, compare both sides of the equation. If the variable terms are the same and the constant terms are different, then the equation has no solutions.

3 0
3 years ago
Given a sample space, and events A and B, where P(A)= 0.5 and P(B)=0.5. Which of the following values for P(A and B) are not pos
user100 [1]

Option a, option b, option c, option d are not possible values for P(A ∩ B)

Solution:

Given A and B are independent events.

P(A) = 0.5 and P(B) = 0.5

To find which of the following values for P(A and B) are not possible.

P(A and B) = P(A ∩ B)

P(A ∩ B) = P(A) × P(B)

              = 0.5 × 0.5

P(A ∩ B) = 0.25

Option a: All are possible.

All answers are not possible for two independent events.

Option b: 0.35

We found that P(A and B) is 0.25.

So, 0.35 is not possible value.

Option c: 0.5

We found that P(A and B) is 0.25.

So, 0.5 is not possible value.

Option d: 0

We found that P(A and B) is 0.25.

So, 0 is not possible value.

Option e: 0.25

We found that P(A and B) is 0.25.

So, 0.25 is the possible value.

Hence, 0.35, 0.5, 0 are not possible values.

4 0
3 years ago
According to the Sleep Foundation, the average night's sleep is 6.8 hours (Fortune, March 20, 2006). Assume the standard deviati
vivado [14]

Let X be the random variable for the time a given person from the population spends sleeping. With X\sim\mathcal N(6.8,0.4^2) we have

P(X>8)=P\left(\dfrac{X-6.8}{0.4}>\dfrac{8-6.8}{0.4}\right)=P(Z>3)\approx0.0013

where Z\sim\mathcal N(0,1^2).

P(X\le6)=P\left(\dfrac{X-6.8}{0.4}\le\dfrac{6-6.8}{0.4}\right)=P(Z\le-2)\approx0.0228

P(7

Rounded to the nearest whole number, that comes out to about 31%.

5 0
3 years ago
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