Question

What is the equation of a line that is parallel to y=6x+7 and passes through (0,9)

Answer 1

Answer: The equation of a line that is parallel to y=6x+7 and passes through (0,9) is y=6x+9.

Explanation:

The equation of given line is

$y=6x+7$

The slope intercept form of a line is,

$y=mx+b$

Where, m is slope and (0,b) is y intercept.

On comparing the given equation with slope intercept form we get,

$m=6$

The slope of the given line is 6.

Since the slope of parallel line are equal, therefore the slope of required line is 6.

The point slope form of a line.

$y-y_1=m(x-x_1)$

The slope of required line is 6 and it passing through the point (0,9),

$y-9=6(x-0)$

$y=6x+9$

Therefore the equation of a line that is parallel to y=6x+7 and passes through (0,9) is y=6x+9.