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Daniel [21]
2 years ago
13

Which expression is equivalent to (4x+11)+7x?

Mathematics
1 answer:
Anna007 [38]2 years ago
4 0
HEY THERE FAM.

THE CORRECT ANSWER IS....<span> D.(4x-7x)+11</span>
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What is the equation of the quadratic function represented by this table ??HELP PLEASE GRADUATION IS JUNE FIRST
miss Akunina [59]

9514 1404 393

Answer:

  -3, 7, 8

Step-by-step explanation:

You can fill in the boxes from the table values as shown in the attachment.

The leading coefficient is negative because the parabola opens downward. The value of it is the change in y-value as x changes by 1 unit either side of the vertex.

The vertex is identified by the fact that the y-values are symmetrical either side of the vertex.

5 0
2 years ago
Read 2 more answers
The science club sponser is ordering caps and shirts for the boys and girls in the science club. There are 45 science club membe
mafiozo [28]

Answer:

9 packs of shirts and 15 packs of caps

8 0
3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
X² - xy = 0<br> x + y = 1
wolverine [178]

Answer:

(0, 1 ) and (\frac{1}{2}, \frac{1}{2} )

Step-by-step explanation:

Given the 2 equations

x³ - xy = 0 → (1)

x + y = 1  → (2) ( subtract x from both sides )

y = 1 - x → (3)

Substitute y = 1 - x into (1)

x² - x(1 - x) = 0

x² - x + x² = 0

2x² - x = 0 ← factor out x from each term on the left side

x(2x - 1) = 0

Equate each factor to zero and solve for x

x = 0

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2}

Substitute these values into (3) for corresponding values of y

x = 0 : y = 1 - 0 = 1 ⇒ (0, 1 )

x = \frac{1}{2} : y = 1 - \frac{1}{2} = \frac{1}{2} ⇒ ( \frac{1}{2}, \frac{1}{2} )

3 0
3 years ago
I need the answer for the one that says something about riverside please and thank you
son4ous [18]
The First Answer Should Be 2 Not Four

The Second Answer:

12 : x
4 : 21
Cross Multiply
4x = 252
x = 63
7 0
2 years ago
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