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mestny [16]
3 years ago
12

Tyler needs to get the windows in his new home cleaned. The cleaning company needs to know the total number of window panes befo

re it can tell him how much the job will cost. There are 12 windows, each with four window panes across and four window panes down. Tyler can find the total number of window panes by multiplying the number of windows by the number of panes in each window. The total number of window panes is an expression with a whole-number exponent. Write an expression with exponents to find the total number of panes in 12 windows.
Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
The answer to that question is (4^2)*12
ANTONII [103]3 years ago
3 0

Answer:

I believe it's (4^2)*12

Step-by-step explanation:

To find the correct amount of the window panes there are, we have to find how much window pains are in each of the window's. So we have a 4 by 4 so that's 16. Then we have to do 16*12 to get the total amount of panes since Panes Per Window multiplied by Number Of Windows equals Total Number Of Panes

Hope this helps! ∪ω∪

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PLEASE HELP. IF U GET THIS RIGHT I WILL MARK U BRAINLIEST!!! THANK U GUYS
KatRina [158]

Answer:

2

Step-by-step explanation:

The slope is the rise over the run. 2 simple coordinates I can see is (6,2) and (7,4). I usually like to visualize it instead of actually solving it mathematically. So, we can start at (6,2). The point (6,2) goes up 2 and 1 to the right in order to get (7,4.) So since the slope is rise over run ( y/x) it would be 2/1 because we went 2 up the y axis and 1 to the right of the x axis. So 2/1 is 2. Therefore, 2 is the answer.  I'm sorry if my explaining isn't the best... I hope this helps though!!

6 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
marishachu [46]

Answer:

Thus, the two root of the given quadratic equation  x^2-6=-x  is 2 and -3 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2-6=-x

This can be written as ,  x^2+x-6=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = 1 , c = -6

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(1)\pm\sqrt{(1)^2-4\cdot 1 \cdot (-6)}}{2 \cdot 1}

\Rightarrow x=\frac{-1\pm\sqrt{25}}{2}

\Rightarrow x=\frac{-1\pm 5}{2}

\Rightarrow x_1=\frac{-1+5}{2} and \Rightarrow x_2=\frac{-1-5}{2}

\Rightarrow x_1=\frac{4}{2} and \Rightarrow x_2=\frac{-6}{2}

\Rightarrow x_1=2 and \Rightarrow x_2=-3

Thus, the two root of the given quadratic equation x^2-6=-x is 2 and -3 .

7 0
3 years ago
Read 2 more answers
At a competition 24 of the 40 members of a middle school band won a medal.what percentage of the band won a medal?
Maru [420]

Answer:

60% of the band won a medal.

Step-by-step explanation:

=24/40*100

=2400/40

=60%

Therefore, 60% band won a medal.

7 0
3 years ago
what is the slope of the line that passes through the points (-3,1) and( 7,-14)? write your answer in simplest from.
Harrizon [31]

Answer:

slope = m = (0--3)/(14--4) = 3/18 = 1/6

y=mx + b

y =(1/6)x + b

0= (1/6)14 + b

b = - 14/6 = - 7/3

y = (1/6)x - 7/3

or

6y-x = -14

Step-by-step explanation:

3 0
3 years ago
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