Answer:
Step-by-step explanation:
A third degree polynomial has a <em>total of three roots</em>, real and imaginary combined.
If it already has 2 real roots, -4 and +4, then it has to have three real roots because imaginary roots come in conjugate pairs, i.e. they come in even numbers.
A and b cause there both half’s
(1 + i)/(1 + 2i)
To simplify this, we need to multiply both sides by the conjugate.
(1 + i)(1 - 2i)
1 - 2i - i - 3i^2
Combine like terms.
3i^2 - 3i + 1
i^2 = -1
-3i - 2 is the simplified numerator.
(1 + 2i)(1 - 2i)
1 - 2i + 2i - 4i^2
1 - 4i^2
i^2 = -2
1 + 4
5
<h3><u>The simplified expression is ((-3i)/5) + ((-2)/5)</u></h3>
Use the equation to find the slope: m=y2-y1/x2-x1 and plug in each of the y coordinates into the numerator and each of the x coordinates in the denominator
m=-2-3/4-8
-5/-4
m=5/4
Plug in the slope and one of the ordered pairs into y=mx+b. I’ll use (8,3)
3=5/4(8)+b
3=10+b
-7=b
Equation: y=5/4x-7
16*28=448
28 is 12 inches higher than 16 so it should work.