Question

| 2) through: (-5, -4), perp. to y = -x + 2

Answer 1

Answer:

$y=x+1$

Step-by-step explanation:

Your generic line will be $y= mx+q$, so you'll need two condition.

Since it has to be perpendicular to $y=(-1)x+2$, the product of the slopes needs to be -1, or $m(-1)=-1$, hence your "generic" becomes $y=x+q$. Since it has to pass through [/tex](-5;-4), let's put the coordinates in there: $(-4)=1(-5)+qq-5=-4q=1$

your line becomes $y=x+1$