Porobability distribution of X
x P(x)
0 0.2
1 0.4
2 0.4
Total .1.0
i] Expectation
Mean=Σxp
Variance=x²p-(∑xp)²
thus:
Mean=(0*0.2)+(1*0.4)+(2*0.4)
=0+0.4+0.8
=1.2
ii] Variance
Variance=[(0²*0.2)+(1²*0.4)+(2²*0.4)]-(1.2)²
=[0+0.4+1.6]-1.44
=0.56
hence:
standard deviation=sqrt(0.56)=0.74833
Answer:
Here is your ans.
Step-by-step explanation:
I have few time Because I am too late to school.. So I had solved only up to q.no 5. . Hope you understand it. If you Like then Plz give a five star rating to my ans. And One thing sorry for rough handwriting and mistake
Answer:
Explanation:
You can subtract the second equation from the first equation to eliminate y:
7x + y = 25 – 6x + y = 23: 7x – 6x = x; y – y = 0; 25 – 23 = 2
x = 2
You could also solve one equation for y and substitute that value in for y in the other equation:
6x + y = 23 → y = 23 – 6x.
7x + y = 25 → 7x + (23 – 6x) = 25 → x + 23 = 25 → x = 2
Step-by-step explanation:
we are given
f(x)=[x=1]
where bracket means ceiling functions
we know that
Ceiling function returns the least value of the integer that is greater than or equal to the specified number
so, we can check each options
option-A:

At x=-4:
f(x)=[-4-1] =-5
For x<-3:
Let's assume
x=-3.1
f(x)=[-3.1-1] =[-4.1]=-5
so, this interval is TRUE
option-B:

At x=-2:
f(x)=[-2-1] =-3
For x<-1:
Let's assume
x=-1.1
f(x)=[-1.1-1] =[-2.1]=-3
so, this is FALSE
If the question was -20.48 divided by -4 then the answer is 5.12