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juin [17]
2 years ago
10

Help me to answer this question pl​s

Mathematics
1 answer:
attashe74 [19]2 years ago
8 0

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

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RideAnS [48]

Answer:

\frac{4}{25}

Step-by-step explanation:

there are a total of 20 marbles and the chance that it is blue is 8/20 so multy that by itself and the answer is 4/25

3 0
3 years ago
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Given a 10 foot length of the tree trunk with a radius of 3 feet what is the tree trunk section if it was a density of 45 lb/ft
mezya [45]

Answer:

0.6

Step-by-step explanation:

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3 years ago
Find the projection of u = <–6, –7> onto v = <1, 1> a. <-13/2,-13/2> b. <39,91/2> c. <-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
Could someone please help and explain this to me
Lelu [443]

Answer:

Step-by-step explanation:

Four

Start by trying to understand what f(x) means. First of all it is the same thing as y in the equation given in question 4. It is a shorthand that tells you that you put an x in wherever you see an x on the right.

More important, it tells you what to put in for x on the right.

f(z) would tell you to put z in for x anywhere there is an x on the right.

f(z)=2z+1. It is just a shorthand to tell you what to do on the right.

f(2) means put a 2 in for the x on the right. Read all of this carefully. You need to know it.

f(2) = 2(2) + 1

f(2) = 4 + 1

f(2) = 5

=================

Five

f(x) = -x - 5            The minus 4 is not going to change what you do.

f(-4) = -(-4) - 5        Wherever you see an x you put in a minus 4

f(-4) = 4 - 5

f(-4) = - 1

======================

Just so you know, consider a more complicated example

f(x) = 20x^3 + 7x^2 + 4x + 19

Where ever you see an x put in 2

f(2) = 20*(2^3) + 7*(2^2) + 4(2) + 19

f(2) = 20*8 + 7*4 + 4*2 + 19

f(2) = 160 + 28 + 8 + 19

f(2) = 215

Note x can be anything the question tells you it is.

f(5) means put a 5 in for every x.

8 0
4 years ago
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Lorico [155]
1. The perimeter is 20. How I got that is to add all of them together- 9+3+3+3+2=20. The area is the area is 15. How I got that was I did the little square with 3 and 2 first. 3 times 2 = 6, then I did the 3 and 3 which = 9 and added those together 9+6=15

2. The perimeter is 15. How I got that is I add them all together. 6+3+2+2+2=15. The area is 10. I did 3 times 2 = 6, 2 times 2 = 4, 6+4=10
5 0
3 years ago
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