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rewona [7]
2 years ago
13

the formula for the area o a triangle is 1/2 bh=A. Which of the following is not a possible first step to rearrange this formula

to find the base of the triangle
Mathematics
1 answer:
ella [17]2 years ago
4 0

Answer:

Step-by-step explanation:

1/2 bh=A

to find the base of the triangle you can

divide by h

or multiply by 2

what are the other options given to you?

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A football game in 60 minutes. There are 3:25 minutes left on the clock in the 3rd quarter. How many minutes and seconds have be
Fynjy0 [20]

Answer:

11:35

Step-by-step explanation:

5 0
2 years ago
Fran bought some art supplies from an online retailer. The retailer charges a $5.95 shipping fee or 6% of the total purchase pri
rodikova [14]

Answer:

Step-by-step explanation:

if 124.50 represents  100%

how much x  represents 6% ?

cross multiply

x= 124.50*6/100= 7.47

$7.47 > $5.95 so it will pay $7.47 in shiping

4 0
3 years ago
Read 2 more answers
If a solid has faces that consist of 2 equilateral triangles and 3 congruent rectangles, what type of solid is it?
svlad2 [7]
A right triangular prism is a solid that has faces that consist of 2 equilateral triangles and 3 congruent rectangles. It is also described to have two parallel faces and 3 other faces that belong to the same place (and are not parallel to the parallel pair of faces).
5 0
2 years ago
Evaluate the variable expression x + y for the given values of x and y . X=43.37 ; Y=18.24
cupoosta [38]

Answer:

61.61

Step-by-step explanation:

In the expression now that we know the value of x and y, we can replace it with its values. So it would look like this.... 43.37 + 18.24. This equals 61.61.

Hope this helps!

4 0
2 years ago
Verify the following identity and show steps<br><br> (Cos2 θ)/(1+sin2 θ)= (cot θ-1)/(cot θ+1)
Paul [167]

Answer:

Verified below

Step-by-step explanation:

We want to show that (Cos2θ)/(1 + sin2θ) = (cot θ - 1)/(cot θ + 1)

In trigonometric identities;

Cot θ = cos θ/sin θ

Thus;

(cot θ - 1)/(cot θ + 1) gives;

((cos θ/sin θ) - 1)/((cos θ/sin θ) + 1)

Simplifying numerator and denominator gives;

((cos θ - sin θ)/sin θ)/((cos θ + sin θ)/sin θ)

This reduces to;

>> (cos θ - sin θ)/(cos θ + sin θ)

Multiply top and bottom by ((cos θ + sin θ) to get;

>> (cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ)

In trigonometric identities, we know that;

cos 2θ = (cos² θ - sin²θ)

cos²θ + sin²θ = 1

sin 2θ = 2sinθcosθ

Thus;

(cos² θ - sin²θ)/(cos²θ + sin²θ + 2sinθcosθ) gives us:

>> cos 2θ/(1 + sin 2θ)

This is equal to the left hand side.

Thus, it is verified.

5 0
2 years ago
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