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fomenos
3 years ago
14

(8x10^-3) ÷ (2x10^-4)​

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

40

Step-by-step explanation:

8*10^-3=0.003

2*10^-4=0.0002

0.003÷0.0002=40

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Answer:

E=h*mg

Step-by-step explanation:

3=6/2

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4 0
3 years ago
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A person lost in an office building travels up 3 floors in an
soldier1979 [14.2K]

Answer:

B. +3 - 1 + 5 - 4

Step-by-step explanation:

The plus means going up and the negative means you are going down.

You are going up 3 floors (+3)

You are going down 1 floor ( -1)

You are going up 5 floors (+5)

You are going down 4 floors (-4)

Let me know if this helps!

6 0
3 years ago
Find the slope and Y-intercept of the graph of this equation <br><br> y-9x=1/2
natita [175]
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Your answer would be:

Y=9x+1/2

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4 0
3 years ago
A41.0m guy wire is attached to the top of a 32.8 m antenna and to a point on the ground. How far is the point on the ground from
Setler79 [48]

Answer:

Step-by-step explanation:

A right angle triangle is formed.

The length of the guy wire represents the hypotenuse of the right angle triangle.

The height of the antenna represents the opposite side of the right angle triangle.

The distance, h from base of the antenna to the point on the ground to which the antenna is attached represents the adjacent side of the triangle.

To determine h, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

41² = 32.8² + h²

1681 = 1075.84 + h²

h² = 1681 - 1075.84 = 605.16

h = √605.16

h = 24.6 m

To determine the angle θ that the wire makes with the ground, we would apply the the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos θ = 24.6/41 = 0.6

θ = Cos^-1(0.6)

θ = 53.1°

7 0
4 years ago
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
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