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fomenos
3 years ago
14

(8x10^-3) ÷ (2x10^-4)​

Mathematics
1 answer:
Lorico [155]3 years ago
5 0

Answer:

40

Step-by-step explanation:

8*10^-3=0.003

2*10^-4=0.0002

0.003÷0.0002=40

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Answer the following True or False:
Ilia_Sergeevich [38]

False; consider as a counterexample the function <em>f</em> : ℝ→ℝ defined by

f(x)=\begin{cases}-3&\text{for }x\neq2\\0&\text{for }x=2\end{cases}

Clearly <em>f</em> approaches -3 as <em>x</em> gets closer to -2, but neither limit from either side is equal to the function's value at <em>x</em> = 2 (that is, -3 ≠ 0), so <em>f</em> is not continuous.

4 0
3 years ago
The scores on an achievement test are normaly distributed with mean µ = 100 and standard deviation σ = 100. What should the scor
ser-zykov [4K]

Answer:

the student should score atleast 229 to be among the top 10%.

Step-by-step explanation:

in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

P(0.4) = \dfrac{x - \mu}{\sigma}

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.

we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)

looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)

P(0.4015) = \dfrac{x - 100}{100}

1.29 = \dfrac{x - 100}{100}

x = 1.29(100) + 100

x = 229

the student should score atleast 229 to be among the top 10%.

7 0
3 years ago
Rick and two friends share a large bag of popcorn which cost $6.25 and a large soda which cost $3.25. They divide the cost evenl
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Add the prices together
Then divide by 3.

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3 years ago
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7 0
3 years ago
I'm getting confused when i look at this question:
Vladimir [108]
2/9 = 0,222 this is liter what in milliliter will be 222

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hope helped 

3 0
3 years ago
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