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3 years ago

(8x10^-3) ÷ (2x10^-4)

Mathematics

1 answer:

Lorico [155]3 years ago

5 0

Answer:

Step-by-step explanation:

8*10^-3=0.003

2*10^-4=0.0002

0.003÷0.0002=40

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The answer is 445,446

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Mr Johnson was paid $190 for a job that required 40 hours of work. at this rate how much should he be paid for a job requiring 6

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4.75 per hour. So 60 hours would be $285

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3 years ago

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Restaurant L made 6 dumplings more than Restaurant M.

11Alexandr11 [23.1K]

Answer:

I am not completely sure with this

Step-by-step explanation:

L restaurant=6 + M

N Restaurant= 2 x L+M

Total dumplings= 72= (6+M) + M + 2x L+M

Dumplings in N restaurant=

suppose m=2

so L= 6+M=8

so L and M will be 10=8+2

N=10 x 2= 20

so u should try and find out like that

Im in elementary school so im not sure

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2 years ago

Let X be a random variable with probability mass function P(X = 1) = 1 2 , P(X = 2) = 1 3 , P(X = 5) = 1 6 (a) Find a function g

Goryan [66]

The question is incomplete. The complete question is :

Let X be a random variable with probability mass function

P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6

(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.

(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)

Solution :

Given :

$P(X=1)=\frac{1}{2}, P(X=2)=\frac{1}{3}, P(X=5)=\frac{1}{6}$

a). We know :

$E[g(x)] = \sum g(x)p(x)$

So, $g(1).P(X=1) + g(2).P(X=2)+g(5).P(X=5) = \frac{1}{3} \ln (2) + \frac{1}{6} \ln(5)$

$g(1).\frac{1}{2} + g(2).\frac{1}{3}+g(5).\frac{1}{6} = \frac{1}{3} \ln (2) + \frac{1}{6} \ln (5)$

Therefore comparing both the sides,

$g(2) = \ln (2), g(5) = \ln(5), g(1) = 0 = \ln(1)$

$g(X) = \ln(x)$

Also, $g(1) =\ln(1)=0, g(2)= \ln(2) = 0.6931, g(5) = \ln(5) = 1.6094$

b).

We known that $E[g(x)] = \sum g(x)p(x)$

∴ $g(1).P(X=1) +g(2).P(X=2)+g(5).P(X=5) = \frac{1}{2}e^t+ \frac{2}{3}e^{2t}+ \frac{5}{6}e^{5t}$

$g(1).\frac{1}{2} +g(2).\frac{1}{3}+g(5).\frac{1}{6 }= \frac{1}{2}e^t+ \frac{2}{3}e^{2t}+ \frac{5}{6}e^{5t}$$

Therefore on comparing, we get

$g(1)=e^t, g(2)=2e^{2t}, g(5)=5e^{5t}$

∴ $g(X) = xe^{tx}$

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2 years ago

Jake bought a shirt and socks, originally marked $14.99 and $4.99. If both items were 20% off, how much did he pay for both of t

natta225 [31]

(15 +5)*(0.80) = 16

Jake paid ...
(3) $16

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3 years ago

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(8x10^-3) ÷ (2x10^-4)​

(8x10^-3) ÷ (2x10^-4)