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bazaltina [42]
3 years ago
15

The entry fee to a park is $20. Each ride cost $2.50. Jackson spent a total of $35 at the park. How many rides did jackson go on

?
Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0

Answer:

Jackson went on 6 rides.

Step-by-step explanation:

35 - 20, because $20 was originally paid, and we don't need to do anything more with that.

That gives us $15.

$15 divided by $2.50 = 6

Hope this helps!

GenaCL600 [577]3 years ago
5 0

Answer:

6 rides

Step-by-step explanation:

35-$20(entry fee)=$15(amount spent on rides)

15/$2.50(cost of each ride)=6 rides

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MatroZZZ [7]

Answer:

the answer is D

Step-by-step explanation:

I don't know how to explain it very well but the line starts at 2 then ends at 8

6 0
2 years ago
Which expression is NOT equivalent to (a + b)(x + y)? A) (a + x)(b + y) B) (b + a)( y + x) C) (a + b)x + (a + b)y D) a(x + y) +
Tanzania [10]

Answer:

A)

Step-by-step explanation:

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3 years ago
Can You Please Help With Problem 2.
jok3333 [9.3K]
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2 years ago
Read 2 more answers
Which value for the number makes the statement true?
umka21 [38]
A product is the result of multiplication.
A quotient is the result of division.
So you're trying to find the quotient of a number (x) and 5 that equals 8.

Try plugging in the answers. 
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A. x=4
  4/5=8  (Incorrect, 4 divided by 5 is 0.8)

B. x=8
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C. x=40
  40/5=8  (Correct, 40 divided by 5 is 8)

D. x=80
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3 0
3 years ago
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Dmitry_Shevchenko [17]

Mel should use the least  common multiple to solve the problem

<u>Solution:</u>

Given, Mel has to put the greatest number of bolts and nuts in each box so each box has the same number of bolts and the same number of nuts.  

We have to find that should Mel use the greatest common factor or the least common multiple to solve the problem?

He should use least common multiple.

Let us see an example, suppose 12 bolts and nuts are to be fit in 6 boxes.

Then, if we took H.C.F of 12 and 6, it is 6, which means 6 bolts and nuts in each box, but, after filling 2 boxes with 6 bolts and nuts, there will be nothing left, which is wrong as remaining boxes are empty.

So the remaining method to choose is L.C.M.

Hence, he should use L.C.M method.

6 0
3 years ago
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