Question

Solve the system of equations below ?(((:

Answer 1

Hi,
The answer would be D. Here's why.
You could just do trial and error or like an equation but to make it simple, use trial and error since it is only small number.
If x was 5 and y was -4, just replace them into the equations...
4x+y=16. if x=5 and y=-4, then the equation would be 4*5 +(-4)=16 then it would be 20-4=16. 16=16. There first equation solved. Now lets do the next one. 2x+3y=-2. If x=5 and y=-4, then the equation would 2*5+3*(-4)=-2. Simplify and you get 10+(-12)= -2. 10-12=-2. -2=-2
This is why the answer is D (5, -4)
Hope this helps!

Answer 2

Answer:

(5,-4)

Step-by-step explanation:

$4x+y= 16, 2x+3y=-2$

Solve the equation for x and y

Solve the first equation for y

$4x+y= 16$

Subtract 4x on both sides

$y=-4x+16$

Now plug in -4x+16 for x in second equation

$2x+3y=-2$

$2x+3(-4x+16)=-2$

$2x-12x+48=-2$

$-10x+48=-2$

Subtract 48 on both sides

$-10x=-50$

Divide both sides by -10

x=5

Plug in 5 for x in first equation

$y=-4x+16$

$y=-4(5)+16=-4$

Solution is (5,-4)