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san4es73 [151]
3 years ago
10

|x+11| =−1 plz help show steps 2

Mathematics
1 answer:
dezoksy [38]3 years ago
3 0

Answer:

No solutions. You can’t have a negative absolute value.

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Answer:

The set of coefficients asociated with the given polynomial in ascending order is [C] = \{4,0,5\sqrt{3}\}.

Step-by-step explanation:

Let y = 5\sqrt{3}\cdot x^{2}+4, which is a polynomic function, defined as:

y = \Sigma_{i=0}^{n}c_{i}\cdot x^{i} (1)

Where:

c_{i} - i-th Coefficient.

x^{i} - i-th Power.

n - Grade of the polynomial.

We notice that given polynomial has degree 2 and can be rewritten by applying this definition:

y = 4 + 0\cdot x + 5\sqrt{3}\cdot x^{2}

Then, the set of coefficients asociated with the given polynomial in ascending order is:

[C] = \{4,0,5\sqrt{3}\}

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3 years ago
If 8 cakes cost £4.00 how much would 3 cakes cost?
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Hello!

To calculate how much 3 cakes would cost, we must first find the cost of each individual cake.

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This means that each individual cake costs $0.50. Multiply this by 3 to find the cost of 3 cakes.

0.50 × 3 = 1.50

Therefore, 3 cakes would cost $1.50.
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Because $5 is a one time charge.
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Keep in mind that whenever you have a variable inside an expression, you have to think of it as a placeholder, hiding a certain value which we haven't specified yet.


Expressions with variables are a mean to express the generic idea underneath the expression, rather than its particular value.


So, an expression like x-7 represents the idea of subtracting 7 from a particular number. Once you give a specific value to x, the expression will become an actual subtraction between numbers, and you will be able to compute its value.


So, we have several values for x, which are several ways to turn our "abstract" subtraction into an actual, computable subtraction.


If x = 12, the expression becomes 12-7 and it evaluates to 5.


If x = 19, the expression becomes 19-7 and it evaluates to 12.


If x = 17, the expression becomes 17-7 and it evaluates to 10.


If x = 6, the expression becomes 6-7 and it evaluates to -1.


If x = 5, the expression becomes 5-7 and it evaluates to -2.

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