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Brrunno [24]
3 years ago
8

A machine drops 74 milliliters of liquid into a beaker every minute. Using an empty beaker, Sarah started the machine and left t

he room. When she returned, the beaker had 1,850 milliliters of liquid in it. Select the correct operation that can be used to find the time in minutes, m, that Sarah was out of the room, and then find the value of m. Sarah was out of the room for minutes.
Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

Division, you can divide the total amount of total milliliters buy the number of milliliters dropped every minute. 1850/74= 25. So m= 25. Sarah left the room for 25 minutes

Step-by-step explanation:

pls mark me brainliest

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krek1111 [17]

Answer:

(5,225)

Step-by-step explanation:

The break even point is when the cost equals the revenue.

C=R

15x+150=45x

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Plug this back into the original equations to get the y value.

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3 years ago
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Sidana [21]

Answer:

D: 14q + 21√qr

Step-by-step explanation:

We want to find the product of;

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Correct option is D

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8 0
3 years ago
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Select the correct answer from each drop-down menu.
Ket [755]

Answer:

Correlation coefficient ≈ 0.9445

This indicates that the weight of a student increases as the height of the student increases.

Step-by-step explanation:

The rest of the question is the following table

value of x (<u>height</u>) are        58, 59,   60,  62,  63,  64,   66,  68,  70

Value of y (<u>weight</u>) are:      122, 128, 126, 133, 145, 136, 144, 150, 151

=======================================================

To calculate the correlation coefficient we will use the following form:

r = \frac{n(\sum xy)- (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2} \sqrt{n\sum y^2-(\sum y)^2} }

So, n (the number of terms) = 9

∑x = 570, ∑y= 1236, ∑ x²= 36234, ∑ y²= 170694 and ∑xy=78617

So, the correlation coefficient =

r = \frac{9\times 78617- 570\times 1236}{\sqrt{9\times 36234-(570)^2}\sqrt{9\times 170694-(1236)^2}}\\

∴ r =  0.9445

So, weight of a student increases as the height of the student increases.

5 0
3 years ago
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Answer:

Combine like terms

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