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Airida [17]
3 years ago
11

What is the sum of (q+r)-(r+10)

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
6 0

Answer:

q+10 is the answer

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Long Division: (3x^4-8x^3-x^2+9x+5) / (x-2) pleaseee answer this
Drupady [299]

3<em>x</em>⁴ = 3<em>x</em>³ • <em>x</em>, and

3<em>x</em>³ (<em>x</em> - 2) = 3<em>x</em>⁴ - 6<em>x</em>³

Subtract this from the numerator to get a remainder of

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (3<em>x</em>⁴ - 6<em>x</em>³) = -2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5

-2<em>x</em>³ = -2<em>x</em>² • <em>x</em>, and

-2<em>x</em>² (<em>x</em> - 2) = -2<em>x</em>³ + 4<em>x</em>²

Subtract this from the previous remainder to get a new remainder of

(-2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (-2<em>x</em>³ + 4<em>x</em>²) = -5<em>x</em>² + 9<em>x</em> + 5

-5<em>x</em>² = -5<em>x</em> • <em>x</em>, and

-5<em>x</em> (<em>x</em> - 2) = -5<em>x</em>² + 10<em>x</em>

Subtract this from the last remainder to get a new one of

(-5<em>x</em>² + 9<em>x</em> + 5) - (-5<em>x</em>² + 10<em>x</em>) = -<em>x</em> + 5

-<em>x</em> = -1 • <em>x</em>, and

-1 (<em>x</em> - 2) = -<em>x</em> + 2

This gives a new remainder of

(-<em>x</em> + 5) - (-<em>x</em> + 2) = 3

3 does not divide <em>x</em>, so we're done.

So, we have

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) / (<em>x</em> - 2) = 3<em>x</em>³ - 2<em>x</em>² - 5<em>x</em> - 1 + 3/(<em>x</em> - 2)

7 0
3 years ago
Please help!<br> 10<br> ∑ 2i-9<br> i=3
pentagon [3]

\sum\limits_{i=3}^{10}(2i-9)=2(3)-9+2(4)-9+2(5)-9+2(6)-9+2(7)-9\\\\+2(8)-9+2(9)-9+2(10)-9\\\\=6-9+8-9+10-9+12-9+14-9+16-9+18-9+20-9\\\\=90-72=18

6 0
3 years ago
Someone help me pls <br><br>47 as the sum of ______
Elanso [62]

9514 1404 393

Answer:

  (a) 6² +3² +1² +1² = 47

  (b) 5² +4² +2² +1² +1² = 47

  (c) 3³ +4² +2² = 47

Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

__

(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

__

(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

3 0
3 years ago
How many students were enrolled by the end of the fourteenth century at the university of salamanca?
zmey [24]
There were about 500 to 600 students that attended the University of salamanca by the end of the 14th century
5 0
3 years ago
What is the square root of 50 to the nearest tenth
krok68 [10]
7.07 so I think you'd leave it at 7 for your answer
7 0
3 years ago
Read 2 more answers
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