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3 years ago

To solve 30times60,think

2 answers:

wel3 years ago

7 0

If you’re asking for a possible strategy for solving this question you can think about annexing zeros. Think 3 x 6, then add the zeros from the numbers which gives us: 3 x 6 = 18, add the zeros we took out in the beginning, giving you 1,800 as the final answer

PIT_PIT [208]3 years ago

3 0

I’m a bit confused for what answer ur asking for but they 30x60=1800

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Find the volume of the cylinder in terms of pi.

Allushta [10]

Answer:

$\large\boxed{V=81\pi\ in^3}$

Step-by-step explanation:

The formula of a volume of a cylinder:

$V=\pi r^2H$

r - radius

H - height

We have r = 3in and H = 9in. Substitue:

$V=\pi(3^2)(9)=\pi(9)(9)=81\pi\ in^3$

5 0

3 years ago

Hey scale drawing of Jamy’s living room is 4cm in width and 6cm length. If each 2cm on the scale drawing equals 8 feet what are

igor_vitrenko [27]

2 cm = 8 feet.
4 / 2 = 2. 8 * 2 = 16. 16 feet in width.
Now, the length:
6 / 2 = 3. 8 * 3 = 24. 24 feet in length.
The actual dimensions are 16 feet in width and 24 feet in length.

5 0

3 years ago

Help with geometry? Can't do it no matter what I try

Anarel [89]

R u in k12? or nah if yes send a mail to the teach

4 0

3 years ago

The length of a room is 4 feet less than twice its width. The perimeter of

AlladinOne [14]

L=2W-4

PERIMETER=2L+2W

58=2(2W-4)+2W

58=4W-8+2W

58=6W-8

6W=58+8

6W=66

W=66/6

W=11 ANS. FOR THE WIDTH.

L=2*11-4

L=22-4

L=18 ANS. FOR THE LENGTH.

PROOF:

58=2*18=2*11

58=36+22

58=58

5 0

3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago