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Vlad1618 [11]
3 years ago
7

Christine runs 10 miles in 75 minutes. At the same rate, how many miles would she ru I miles

Mathematics
1 answer:
Len [333]3 years ago
7 0

Answer:

\frac{46}{5}  miles  [or, 9.2 miles]

Step-by-step explanation:

<u>Complete Question:</u>

Christine runs 10 miles in 75 minutes. At the same rate, how many miles would she ru n in 69 minutes?

<u>Solution:</u>

We need to find the unit rate first and then find our answer. To get unit rate, we need to know the number of miles she runs in "1 minute". So, we will divide number of miles by number of minutes, that is given. Hence:

\frac{10}{75}=\frac{2}{15}

That means in 1 minute, Christine runs 2/15th of a mile.

Now, we want to know how many miles she will run in 69 minutes. We simply multiply unit rate (2/15) by the number of minutes (which is 69). Thus we have:

\frac{2}{15}*69=\frac{2*23}{5}=\frac{46}{5}

In decimal, doing division, that is 9.2 miles

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Find the midpoint of the segment with the following endpoints.<br> (1,-10) and (8,-4)
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Answer:

(4.5,-7)

Step-by-step explanation:

you add the x coordinates then divide them by 2

And then add the y coordinates then divide them by 2 also

3 0
4 years ago
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
3 years ago
Which ratio correctly compares 150 mm to 60 cm?
deff fn [24]
1 to 4
150mm is the same as 15cm
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both divisible by 15
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1 to 4
6 0
3 years ago
Find a degree 4 polynomial having zeros -8,-1,4 and 5 and the coefficient of x^4 equal 1.
Keith_Richards [23]

Answer:

  x^4 -53x^2 +108x +160

Step-by-step explanation:

If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...

  p(x) = (x +8)(x +1)(x -4)(x -5)

Multiplying these out gives the polynomial in standard form.

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We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.

  = (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)

  = x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160

  p(x) = x^4 -53x^2 +108x +160

_____

The graph shows this polynomial has the required zeros.

4 0
4 years ago
the number of students in the four sixth-grade classs at northside school are 26, 19,34 and 21. Use properties to find the total
Aleks04 [339]
In this case all you do is add all the numbers, answer is 100

4 0
3 years ago
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