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Assoli18 [71]
3 years ago
6

How do you solve this

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
8 0

Answer:

(AD)=SQRT(20n^2+34-4n)

Step-by-step explanation:

let the point of intersection between AC and DB be O. Then the length of OA is the same as that of OC which is=2n+5

Similarly the length of DO is the same as that of OB which is=4n-3

Now from Pathagoras theorem we get

(AD)=SQRT((DO)^2+(OA)^2)

(AD)=SQRT((4N-3)^2+(2N+5)^2)

(AD)=SQRT((16n^2+9-24n)+(4n^2+25+20n))

(AD)=SQRT(20n^2+34-4n)

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The sum of, half of a number and double the number is 20. Find the number.​
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Answer:

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Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
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A motorboat can maintain a constant speed of 15 miles per hour relative to the water. The boat makes trip upstream to a certain
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Answer:

The speed of the current is 2 miles per hours

Step-by-step explanation:

Given as :

The speed of motorboat = x = 15 miles per hour

The time taken by motorboat trip upstream = 51 minutes

The time taken by motorboat trip downstream = 39 minutes

Let The speed of the current = y miles per hour

Let The total distance cover = A miles

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So, x - y = \dfrac{A}{51}

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And x + y = \dfrac{A}{39}

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\dfrac{x-y}{x+y} = \dfrac{39}{51}

I.e \dfrac{x-y}{x+y} = \dfrac{13}{17}

Or, 17 × (x - y) = 13 × (x + y)

Or, 17 x - 17 y = 13 x + 13 y

Or, 17 x - 13 x = 13 y + 17 y

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∴   y = 2 miles per hour

Hence The speed of the current is 2 miles per hours   Answer

8 0
3 years ago
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