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VikaD [51]
4 years ago
6

Rework problem 7 from section 3.4 of your text, involving the selection of a colored ball from one of three bowls. Assume that y

ou randomly pick one of the bowls: X, Y, or Z. You then randomly draw one ball out of the selected bowl and note its color. The bowls contain the following colored balls: Bowl X: 2 red, 2 white, and 3 blue. Bowl Y: 2 red, 1 white, and 1 blue. Bowl Z: 1 red, 3 white, and 2 blue. (1) If the ball is blue, what is the probability that it was drawn from bowl X? (2) If the ball is either blue or white, what is the probability that it was drawn from bowl Y?
Mathematics
1 answer:
allochka39001 [22]4 years ago
4 0

Answer:

  • Question (1): 1/2 = 0.5

  • Question (2): 1/6 ≈ 0. 17

Explanation:

<u>1. Arrange the information of the balls contained in the bowls in a table:</u>

                       Bowl X      Bowl Y       Bowl Z     Total

Red balls              2               2                1               5

White balls           2                1                3              6

Blue balls             3                1                2              6

                           ==============================

Totals                     7                4              6             17  

<u>2. To answer each question use the basic definition of probabilities</u>

  • Probability = # of favorable events / # of possible events

<u>3. Question (1) If the ball is blue, what is the probability that it was drawn from bowl X? </u>

<u />

  • Number of total blue balls: 6
  • Number of blue balls in the bowl X: 3
  • Probability that a ball that is blue was drawn from the bowl X: P (b/X)

       P (b/X) = number of blue balls in the bowl X / total number of blue balls = 3 / 6 = 1/2 = 0.5

       

<u>4. Question (2) If the ball is either blue or white, what is the probability that it was drawn from bowl Y?</u>

  • Number of total blue and white balls: 6 + 6 = 12
  • Number of blue balls and white balls in the bowl Y: 1 + 1 = 2
  • Probability that a ball that is either blue or white was drawn from the bowl Y: P (b or w / Y)

       P (b or w /Y) = number of blue balls and white balls in the bowl Y / total number of blue balls and white balls = 2 / 12 = 1/6 ≈ 0.17

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Step-by-step explanation:

The given is,

               A rectangle field has an area of 40 cm^{2}

               If one side of the field is 3 cm longer than the other side

               The length of new area in each side is increased by 10%

Step:1

          Let,

                          b - One side of rectangle

                          l - Other side of rectangle

          From given.

                         l -  b +3

           Formula for area of rectangle,

                   Area, a = lb      

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           Solving the above the equation,

                          b = 5 cm

                            l = 8 cm

Step:2

          If the area of rectangle increased by 10%,

                            l = 8 + ( 8 × \frac{10}{100} )

                              = 8.8

                           b = 5 + ( 5 × \frac{10}{100} )

                              = 5.5

         Area of rectangle is,

                      a = ( 8.8 × 5.5 )

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Result:

        The area of the field where the length of each side is increased by 10% is 48.4 cm^{2}, if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.

             

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