Answer: D) 20
<u>Step-by-step explanation:</u>
Use log rules to convert log into exponent:
P = 0.11
1-p = .89
n = 200
mean = n*p = 22
std dev = n*sqrt(p(1-p)/n) = 4.425
find z values for standard normal distribution
Z= (30-22)/4.425 = 1/808
look up table to find P(Z less than 1.808) which is same P(x less than 30)
for 2nd part, you need 2 Z values
Z1 = (25-22) / 4.425 = 0.678
Z2 = (15-22) / 4.425 = -1.58
P(-1.58 less than Z less than 0.678) = P(Z less than .678) - P(Z less than - 1.58)
Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Answer:
<h2>x =3.6</h2>
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
