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3 years ago

You want to buy an item that cost $100. Which of these is the most cost-effective choice for buying the item

1 answer:

5 0

the one that is the most cost-effective choice for buying the item would be : C. buying it a percent discount without sales tax

With this option, you can get a clear $ 10 cut which is higher compared to the other options

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Please help me!

ladessa [460]

I’ve never done a tape diagram before (so this might be wrong). But I think it’s:

6t=9

If this is correct, I hope it helps :)

3 0

3 years ago

Read 2 more answers

Which term best describes the definition below?

Amiraneli [1.4K]

When a set of objects are chosen from a larger set in which the order of the object doesn't matter, we call this combination. Otherwise if the order of selection would matter this would be called a permutation.
Probability is the likelihood of selecting a particular specified object in from a specified group of objects.
Therefore our answer is B.

4 0

4 years ago

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

3 years ago

I NEED HELP ASAP ILL GIVE 14 POINTS

Kobotan [32]

Answer:

E. 35°, 70°

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the answer to 36+42=6(6+□)

Vsevolod [243]

Answer:

Step-by-step explanation:

36+42=6(6+□)

78= 6 (6+n)

78/6 = 6/6 (6+n)

13=(6+n)

13-6 = (6-6 +n)

7= n

4 0

3 years ago