Simplify \frac{21}{2}x
2
21
x to \frac{21x}{2}
2
21x
\frac{21x}{2}-\frac{3}{4}(2x+5)=\frac{3}{8}
2
21x
−
4
3
(2x+5)=
8
3
2 Simplify \frac{3}{4}(2x+5)
4
3
(2x+5) to \frac{3(2x+5)}{4}
4
3(2x+5)
\frac{21x}{2}-\frac{3(2x+5)}{4}=\frac{3}{8}
2
21x
−
4
3(2x+5)
=
8
3
3 Multiply both sides by 44 (the LCM of 2, 42,4)
42x-3(2x+5)=\frac{3}{2}42x−3(2x+5)=
2
3
4 Expand
42x-6x-15=\frac{3}{2}42x−6x−15=
2
3
5 Simplify 42x-6x-1542x−6x−15 to 36x-1536x−15
36x-15=\frac{3}{2}36x−15=
2
3
6 Add 1515 to both sides
36x=\frac{3}{2}+1536x=
2
3
+15
7 Simplify \frac{3}{2}+15
2
3
+15 to \frac{33}{2}
2
33
36x=\frac{33}{2}36x=
2
33
8 Divide both sides by 3636
x=\frac{\frac{33}{2}}{36}x=
36
2
33
9 Simplify \frac{\frac{33}{2}}{36}
36
2
33
to \frac{33}{2\times 36}
2×36
33
x=\frac{33}{2\times 36}x=
2×36
33
10 Simplify 2\times 362×36 to 7272
x=\frac{33}{72}x=
72
33
11 Simplify \frac{33}{72}
72
33
to \frac{11}{24}
24
11
x=\frac{11}{24}x=
24
11
X=11 over 24
Answer:
The expression for the average number of tickets sold per school child is:
Step-by-step explanation:
The average number of tickets sold per school child is the weighted mean calculus between the number of tickets sold by these classes and the number of children in each classes.
This is the multiplication between the number of tickets sold by these classes and the number of children in each classes divided by the total weight(in this exercise, the total weight is the total number of school child).
So, the expression for the average number of tickets sold per school child is:
How to reduce (simplify) ordinary fraction 8/21? Fraction can't be reduced (simplified). 8/21 = 0.380952380952; Result written as a positive proper fraction and a decimal number. Ordinary (simple, common) math fraction reducing to lowest terms (simplifying), answer with explanations below
Answer:
5.54 miles
Step-by-step explanation:
1. Assume she runs up to a point that is x miles to the east of the coral reef:
distance running =
distance swimming =
2. Times:
time= distance / speed
time running =
time swimming =
3. Total time
time running + time swimming:
4. Minimize time
The minimum time is when the derivative of the function of time is zero.
Find the derivative of T(x), using rule of the sum, the derivative of the sum is the sum of the derivatives, and the chain rule:
Solve for x:
5. Distance the visitor should run to minimize the time
Hence, the visitor should run 5.54 miles.
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