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3 years ago

Between which two whole numbers does square root of 150 lie

Mathematics

1 answer:

hjlf3 years ago

5 0

5 and 6

√150 = 5.31 to 2 dp
5 < 5.31 < 6

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Jalen has a scale model of a train. 2 centimeters in the

mariarad [96]

Answer:

15.3feet

Step-by-step explanation:

Given the scale model of a train as;

2cm = 3feet

We are to find the height of real train of height 10.2cm, we can write;

10.2cm = x

Divide both expressions

2/10.2 = 3/x

2x = 3×10.2

2x = 30.6

x= 15.3

Hence the height if the real train is 15.3feet

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3 years ago

Find the measure of each numbered angle for each figure

cricket20 [7]

Answer:

Angle 1 is 58. Angle 2 is 32.

Step-by-step explanation:

The measure of Angle ACB is 90 because C is on the circle and A and B connect to form a diameter of the circle. So, Angle 1 and Angle 2 add up to 90 (total degrees in triangle - 90). Now you can add the expressions the question gave for Angle 1 and Angle 2, and you get 7x + 6. So you have the equation 7x + 6 = 90. Solve the equation and you get x = 12. Now you can plug in that value for x into the expressions for Angles 1 and 2 to find their measures.

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3 years ago

For the function below, state the x-coordinate of the x-intercept that is located to the fight of the origin.

OLga [1]

Answer:

x = 3

Step-by-step explanation:

It should NOT be "fight of the origin", rather "right of the origin".

Now let's move on to solve the question...

The x-intercept is found by setting the function equal to 0. Thus:

0 = x^3 - 9x

Let's solve this using algebra:

$0=x^3-9x\\0=x(x^2-9)\\0=x(x-3)(x+3)$

Hence, x = -3 and x = 3

The coordinate that is to the right of the origin is the positive one, so x = 3 is the x-intercept we are looking for.

3 0

3 years ago

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Can anyone explain this to me??

finlep [7]

It is the first option. DF = DE. It is referring to the lengths of each line, DE and DF look like they are the same. It is not a scalene triangle it is a right triangle. EF is way too long to be equal to DE or DF

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3 years ago

Divide the combinations. 60C3 / 15C3

Mariulka [41]

I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number

nCr= $\frac{n!}{r!(n-r)!}$
so
$\frac{60C3}{15C3}$ =
$\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }$ =
$( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})$ =
$( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})$ =
$\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}$ =
$\frac{(60!)(12!)}{(57!)(15!)}$ =
$\frac{(60!)}{(57!)(15)(14)(13)}$ =
$\frac{(60)(59)(58)}{(15)(14)(13)}$ =
$\frac{(30)(59)(58)}{(15)(7)(13)}$ =
$\frac{(6)(59)(58)}{(3)(7)(13)}$ =
$\frac{6844}{91}$

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3 years ago

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