Answer:
fourth one
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that
Slope m=-3
A point (x, y)=(4,-2)
Equation of a line can generally be written as
y=mx+c
Where, m is the slope
And c is the intercept on y-axis
Since we are given m=-3
Then, y=mx+c becomes
y=-3x+c
To get c, let substitute the point given, i.e x=4 and y=-2
y=-3x+c
-2=-3(4)+c
-2=-12+c
-2+12=c
c=-2+12
c=10
y=mx+c, then m=-3 and c=10
Then, the equation the line becomes y = -3x + 10
This is the required line equation
The slope of a horizontal line will have a value equal to 0:
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4
Answer: the equation for the horizontal line that contains the point E, would be:
y=-4
We can say L as length and W as the width
L= 3w + 8
The formula for perimeter is 2L + 2W = P. We can substitute L in as "3w+8" to make the equation...
2(3w+8)+2w=88 Now, we can simplify by distributing the 2 to each term
6w+16+2w=88
8w+16=88 Then subtract 16 from each side..
8w=72
w=9
So the width is 9, so we can substitue that into the previous equation, L = 3w+8.
L=3(9)+8
L=27+8
L=35, W=9
