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mars1129 [50]
3 years ago
13

Four sizes of scaled text are shown. Four rows of text and numbers. The first row contains a question mark followed by the phras

e Website text size. The next row contains the number one followed by the phrase Website text size, but smaller than the previous row. The third row contains the number zero point nine three seven followed by the phrase Website text size, but smaller than the previous row. The fourth row contains the number zero point eight seven eight followed by the phrase Website text size, but smaller than the previous row. What is the unknown scale size? Enter your answer as a decimal in the box. Round only your final answer to the nearest thousandth.

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

1.067 would be the answer your looking for in this question.

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Given the system of equations, match the following items.
nadya68 [22]

Answer:

The first picture is 1., second picture is 3, and third picture is 2

7 0
3 years ago
Identify the sequence as arithmetic geometric or neither -8, -3, 6, 11, -22
melomori [17]

Answer:

Neither

Step-by-step explanation:

Check if it's arithmetic:

-8, -3, 6, 11, -22

+5  +6   +5  -33

Nope

Check if geometric:

-8, -3, 6, 11, -22

*3/8  *-2 *11/6 *-2

Nope

So it's neither

5 0
3 years ago
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
F(t) = 2t - 3 evaluate the function
Olenka [21]

Answer:

t ∈   ℝ

Step-by-step explanation:

6 0
3 years ago
Kevin is twice as old as Sean. Together their ages add up to 75.
marissa [1.9K]

Answer:

Kevin would be 50 and Sean would be 25

Step-by-step explanation:

Assuming that there is no other information given,

and Kevin is twice as old as sean, and they gotta add up to 75 total

50 + 25 = 75

25x2 = 50

Hope this helped!

8 0
3 years ago
Read 2 more answers
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