The equation of the line will be 3y + 8x = 165.
<h3>What is an equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
Given that:-
- Find the equation of the line through point (8,−9) ( 8, − 9 ) and perpendicular to 3 x + 8 y = 4.
The given equation of the line is:-
3 x + 8 y = 4.
The slope of this line will be:-
3 x + 8 y = 4.
8y = -3x + 4
y = -3 /8x + ( 1 / 2)
y = mx + c
m = -3 / 8
Since the line is perpendicular to the other line 3x +8y = 4 so the slope will be inverse and negative for the line.
So the slope of the line will be -8 / 3
The equation of the line passing through the point will be given as:-
y - y 1 = m ( x- x1)
y - (-9) = ( -8 / 3) ( x - 8)
Y + 9 = ( -8 / 3 ) ( x -8 )
3 y = -8x + 165
3y + 8x = 165
Therefore the equation of the line will be 3y + 8x = 165.
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To be similar ratios of the corresponding sides should be constant.
|UV|/|EO| = 8/4=2/1
|VL|/|OG| = 4/2=2/1
|LU|/|GE| = 6/3 = 2/1
So,all three corresponding pair of these triangles UVL and EOG are in proportion, so ΔUVL and ΔEOG are similar.
Because ΔUVL and ΔEOG are similar, their corresponding angles are congruent.
m∠U=m∠E
m∠V=m∠O
m∠L=m∠G.
325 - 7 = 318
318/6 = 53 people per bus
Answer:
The correct option is (a).
Step-by-step explanation:
The vertices are equidistant from the circumcenter.
Circumcenter of a triangle is a point where the perpendicular bisectors are intersection each other.
In figure (a) the point P is the intersection point of all perpendicular bisector, therefore point P is the circumcenter of triangle ABC and the point P is equidistant from A,B and C.
Therefore option (a) is correct.
In figure (b) the point P is the intersection point of all perpendicular, therefore point P is not the circumcenter of triangle ABC.
Therefore option (b) is incorrect.
In figure (c) the point P is the intersection point of all bisectors, therefore point P is not the circumcenter of triangle ABC.
Therefore option (c) is incorrect.
In figure (d) the point P is the intersection point of all medians, therefore point P is not the circumcenter of triangle ABC.
Therefore option (d) is incorrect.
