Answer:
D
Step-by-step explanation:
Given the quadratic
d = - 16t² + 12t ← subtract d from both sides
- 16t² + 12t - d = 0 ← in standard form
with a = - 16, b = 12, c = - d
Use the quadratic formula to solve for t
t = ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 
) / - 32
= ( - 12 ± 4
) / - 32
= 
± 
= 
± 
= ± 
→ D
Answer:
<em>(IQR) interquartile range: 12 - 9 = 3</em>
Step-by-step explanation:
Median: 10
Lower quartile: 9
Upper quartile: 12
Interquartile Range: 12 - 9 = 3
Answer:
The answer to your question is:
x = 1
y = 1
z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (1)
-2x - y + z = -3 (2)
2x + 3y + 3z = 5 (3)
Solve (1) and (2)
Multiply 2 by 2
-2x + 2y + 3z = 0
-4x -2y + 2z = -6
-6x + 5 z = -6 (4)
Solve (2) and (3)
Multiply 2 by 3
-6x - 3y + 3z = -9
2x + 3y + 3z = 5
-4x + 6z = -4 (5)
Solve (4) and (5)
Multiply (4) by 2 and (5) by -3
-12x + 10 z = -12
12x - 18z = 12
-6z = 0
z = 0
Then
-4x + 6(0) = -4
-4x = -4
x = -4/-4
x = 1
Finally
-2(1) - y + (0) = -3
-2 - y = -3
-y = -3 + 2
y = 1
