The equation parallel to that passes through the point (-2, 5) is
<u>Solution:</u>
Given that line parallel to that passes through the point (-2, 5)
We have to find the equation of line
Let us first find the slope of line
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ------ eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given equation of line is:
-------- eqn 2
On comparing eqn 1 and eqn 2,
Thus the slope of line "m" =
We know that slope of parallel lines are equal
So slope of line parallel to is also
Now let us find the equation of line with slope and passes through point (-2, 5)
Substitute "m" and (x, y) = (-2, 5) in eqn 1
15 = -2 + 3c
17 = 3c
<em><u>So the required equation is:</u></em>
Substitute "m" and "c" value in eqn 1
Thus the required equation is found