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zloy xaker [14]
3 years ago
8

Your client has saved $1,860 for a down payment on a house. A government loan program requires a down payment equal to 3% of the

loan amount. What is the largest loan amount that your client could receive with this program?
Mathematics
2 answers:
attashe74 [19]3 years ago
7 0

Answer:

5,580

Step-by-step explanation:

1860*3=5,580

Delicious77 [7]3 years ago
6 0

If there is a $5,000 deposit, that means the amount to be mortgaged is $82,500. Calculating 3% of that amount:

0.03 * $82500 = $2475

The closing costs of the loan are $2,475. When they close the deal, they must bring that PLUS the down payment to the table, or $7,475.

(B)

If they are putting 30% down:

0.30 * $310000 = $93000

Add that to all of the other costs listed, they'll need to bring $94,165.

(C)

Discarding the $25,000, the Paltrows are asking for a $100,000 mortgage loan. 2% of that is $2,000, and so the total mortgage is for $102,000.

(D)

I can't answer this because I don't know how the interest is charged

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Construct the 90% confidence interval for the proportion of students at the college who have completed their required English 10
igomit [66]

Answer:

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

8 0
4 years ago
hurry ibwill give brainlest What does Newton's second law of motion state? Every action has an equal and opposite reaction O Abo
Mnenie [13.5K]

Answer:

yes

Step-by-step explanation:

8 0
2 years ago
What do you think the answer is, Hurry.
Svet_ta [14]
The answer of this problem is A because 3 times 21 is 63 and then you plus 1 
which is 64 
4 0
3 years ago
Read 2 more answers
current rules for telephone area codes allow the use of digits 2-9 for the first digit and 0-9 for the second and third digits.
lukranit [14]
In this question, there are 10 digit phone number which was divided into 3-3-4 digits. Every first digit of the division should be 2-9 which mean only 8 possibilities. The other digits would be 0-9 which mean 10 possibilities. Then the calculation would be:

8*10*10   *    8*10*10    *   8*10*10*10  = 8^3 * 10*7= 512 * 10^7= 5.12 * 10^9

If you convert <span>400,000,000 into the scientific form it will become 4* 10^8. Since 5.12*10^9 > 4 * 10^8, then it is clear that the number should be enough</span>
5 0
3 years ago
One of the authors with too much time on his hands weighed each chocolate candy in a bag of 463 plain chocolate candies. Complet
wel

Answer:

a. One of the chocolate candies weighed 0.776 gram and it was heavier than 25 of the other chocolate candies. What is the percentile of this particular​ value?

It is the <u>5</u>th percentile.

b. One of the chocolate candies weighed 0.876 gram and it was heavier than 329 of the other chocolate candies. What is the percentile of this particular​ value?

It is the <u>71</u>th percentile.

c. One of the chocolate candies weighed 0.856 gram and it was heavier than 229 of the other chocolate candies. What is the percentile of this particular​ value?

It is the <u>49</u>th percentile.

Step-by-step explanation:

So when we are talking about percentile, what it means is the point below a certain score or percentage lies, or the rank.

The formula is simple:

Let's call percentile pth, pth=\frac{p}{100}*(n+1)

where p is the position in the data set you want to evaluate (in statistical analysis, these are called quartiles, and they are useful for evaluating groups, so 3 quartiles would divide sample into 25th, 50th and 75th, four quartiles would be 20th, 40th, 60th, 80th, and so on).

and n is the number of elements in the set

For this problem there are no quartiles specified, but we can then work with the definition of percentile, meaning, if you are the 5th percentile, then 95% of the group are above you.

a. So 0.776 was heavier than 25 others, meaning it is in the 26th position out of 463. But we need that in relation to 100, so \frac{26}{463} is 0.0562 or about 5/100, (rounded down). That would mean that the percentile is:

pth=\frac{26}{463}*100=5.62 or 5, rounded down

b. 0.876 was heavier than 329 others, meaning it is in the 330th position out of 463. In relation to 100, so \frac{330}{463} is 0.7127 or about 71/100, (rounded down). That would mean that the percentile is:

pth=\frac{330}{463}*100=71.27 or 71, rounded down

c. 0.856 was heavier than 229 others, meaning it is in the 230th position out of 463. In relation to 100, so \frac{230}{463} is 0.4967 or about 49/100, (rounded down). That would mean that the percentile is:

pth=\frac{230}{463}*100=49.67 or 49, rounded down

3 0
4 years ago
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