1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lapo4ka [179]
3 years ago
11

Please help, almost finished with math

Mathematics
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

i think it is A

Step-by-step explanation:

hope this helped!

p.s it would be cool if you give me brainliest.

HACTEHA [7]3 years ago
3 0
It would be a $16 every 2 pounds
You might be interested in
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
laiz [17]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

8 0
3 years ago
If a man falls and breaks his spine do you
pochemuha

Oh My Gosh!  

My best choice is A.

4 0
3 years ago
Marissa wrote her bike to the park and back up halfway to the park she stopped at the library she was one 310 miles from the lib
erastovalidia [21]

Answer:

5 1/5 miles

Step-by-step explanation:

Given that :

Library is located halfway between park and home ;

Distance between library and park = 1 3/10 miles

Hence, total distance between park and home :

1 3/10 + 1 3/10 = 2 6/10

The distance driven :

Home to park ; park back home

2 6/10 + 2 6/10 = 4 12/10

4 + 12/10 = 4 + 1 2/10

= 5 2/10

= 5 1/5 miles

3 0
3 years ago
find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (-1,9), midpoint: (-9,-10)
Lena [83]
The other endpoint would be (-17,-29)
3 0
4 years ago
If = 12 cm and m=5 cm what is the length of n?<br> A 11 cm<br> B.10 cm<br> C. 13 cm<br> D. 14 cm
Temka [501]

Answer:

C

Step-by-step explanation:

12^2+5^2=c^2

144+25=c^2

169=c^2

Square root 169 and you get 13

7 0
2 years ago
Other questions:
  • Find the length of the radius for the following circle (x+2)^2+y^2=10
    13·1 answer
  • The sum of the squares of three consecutive integers is 194. What are the integers?
    10·1 answer
  • What is the product of 2p + q and -3q - 6p + 1
    11·1 answer
  • Your 401(k) retirement account is currently worth $55,000. Assuming no more contributions, what will your account be worth in 20
    8·1 answer
  • HEEEEEEEEEELLPPP and I will mark you the brainliest because you're clearly smarter than I am.
    12·1 answer
  • Convert the following degrees into radians: 75°
    11·1 answer
  • Who smart enough to answer this?
    11·2 answers
  • If you plan to receive $300 of interest over 15 months on an initial investment of $1200, what is the nominal annual rate of int
    11·1 answer
  • Lauren and Aidan left their offices at 6:15 p.m. and drove to meet at a restaurant the same distance away from their offices for
    13·1 answer
  • Find out which of the linear equations below have a negative slope (select all found)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!