Answer:
Solution given:
The volume of two similar solids are 128 m³
and 250 m³.
surface area of larger solid is 250m²
<u>let</u><u> </u><u>surface</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>smaller</u><u> </u><u>solid</u><u> </u><u>be</u><u> </u><u>x</u><u>.</u>
<u>Since</u><u> </u><u>they</u><u> </u><u>are</u><u> </u><u>similar</u>

x=128
the surface are of the
smaller solid is 128m²
Answer:
A cross-section parallel to the base is a rectangle measuring 15 inches by 8 inches.
A cross-section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.
A cross-section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.
Step-by-step explanation:
the cross sections that are parallel and perpendicular will have the same measurements as the non-intersected sides. the last one will be a diagonal so the intersected edge is 6 and it creates a right triangle so it must be larger than 15 inches.
The equation y=mx+b
Slope= m
y-intercept= b
y= 2x+0 so y=2x
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
565 is the correct answer